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ChemistryLiquid SolutionColligative PropertiesMedium2 minQB

ChemistryMediumnumerical

Passage / Comprehension

A 10% by mass sugar solution has undergone partial inversion according to the reaction: Sugar (aq) + water → Glucose (aq) + Fructose (aq).

After 5 hours from the start of the reaction, the elevation in boiling point of the solution is $5/18$ . The reaction follows first-order kinetics with respect to sugar, and $K_{b}$ for water is $0.57 k g K m o l^{- 1}$ .

The $%$ hydrolysis of sugar at 5 hrs from start of reaction is $10 x %$ . What is the value of ' x '? -

Answer:

5.00

Solution:

$Δ T_{B} = i K_{b} M$

$m = \frac{( 5 ) ( 342 ) ( 9 )}{( 18 ) ( 570 )} = \frac{( 5 ) ( 342 )}{( 1140 )} = \frac{171}{114} = 1.5 i = \frac{( 5 ) ( 342 ) ( 9 )}{( 18 ) ( 570 )} = \frac{( 5 ) ( 342 )}{( 1140 )} = \frac{171}{114} = 1.5 h = \frac{i - 1}{n - 1} = 0.5 % hydrolysis = 50$

Stream:JEESubject:ChemistryTopic:Liquid SolutionSubtopic:Colligative Properties

⏱ 2mℹ️ Source: QB

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