Chemistry - Liquid Solution Question with Solution | TestHub

ChemistryLiquid SolutionRaoult's LawMedium2 minQB

ChemistryMediumnumerical

The vapour pressures of two volatile liquids A and B at $2 5^{\circ} C$ are 50 Torr and 100 Torr, respectively. If the liquid mixture contains 0.3 mole fraction of $A$ , then the mole fraction of liquid $B$ in the vapour phase is $\frac{X}{17}$ The value of $x$ is $____$ .

Answer:

14.00

Solution:

$\frac{y _{B}}{1 - y _{B}} = \frac{P _{B}^{0}}{P _{A}^{0}} [\frac{X _{B}}{1 - X _{B}}]$

$\Rightarrow \frac{y _{B}}{1 - y _{B}} = \frac{100}{50} [\frac{0.7}{0.3}] = \frac{14}{3} \Rightarrow y_{B} = \frac{14}{17}$

Stream:JEESubject:ChemistryTopic:Liquid SolutionSubtopic:Raoult's Law

⏱ 2mℹ️ Source: QB

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