Chemistry - Liquid Solution Question with Solution | TestHub

${\pi }_1=\mathrm{i}$ CRT

${\pi }_1=3(0.02)\mathrm{RT}=0.06\mathrm{RT}$

If $100\mathrm{ml},{\mathrm{BaCl}}_2$ is added then. ${\mathrm{K}}_2{\mathrm{SO}}_4(\mathrm{aq})+{\mathrm{BaCl}}_2(\mathrm{aq})\to {\mathrm{BaSO}}_4(\mathrm{s})+2\mathrm{KCl}(\mathrm{aq})$

$2\mathrm{m}mole$ $4\mathrm{m}mole$ 0 0

0 $2\mathrm{m}mole$ $2\mathrm{m}mole$ $4\mathrm{m}mole$

${\pi }_2=\mathrm{i}$ CRT

${\pi }_2=\frac{[(2\times 3)+(4\times 2)]\mathrm{RT}}{200}$

${\pi }_2=0.07\mathrm{RT}$

$\frac{{\pi }_1}{{\pi }_2}=\frac{0.06\mathrm{RT}}{0.07\mathrm{RT}}=\frac{6}{7}$