Chemistry - Liquid Solution Question with Solution | TestHub

ChemistryLiquid SolutionRaoult's LawMedium2 minQB

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At a given temperature, the vapor pressure of a solution of two volatile liquids A and B is given by the equation:

$P_{S} = 120 - 80 X_{B}$

where $X_{B}$ is the mole fraction of B.

The vapor pressure of pure A and B at the same temperature are, respectively:

Answer:

Solution:

$P_{s} = 120 - 80 X_{B}$

For pure $B, X_{B} = 1, Ps = p^{\circ}_{B} = 40$

For pure $A, X_{B} = 0, Ps = p^{\circ}_{A} = 120$

Stream:JEESubject:ChemistryTopic:Liquid SolutionSubtopic:Raoult's Law

⏱ 2mℹ️ Source: QB

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