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ChemistryLiquid SolutionRaoult's LawMedium2 minQB

ChemistryMediummultiple choice

1 mole benzene ( $p_{benzene}^{0} = 42 mm$ ) and 2 mole toluene ( $p_{benzene}^{0} = 36 mm$ ) will have:

Answer:

A, B

Solution:

$P_{t o t a l} = P_{B}^{0} X_{B} + P_{T}^{0} X_{T}$

$= 42 \times \frac{1}{3} + 36 \times \frac{2}{3} = 38 mm$

$P_{m} Y_{B} = P_{B}^{0} \times X_{B}$

where $Y_{B}$ is the mole fraction of Benzene is vapour phase

$38 \times Y_{B} = 14$

$Y_{B} = \frac{14}{38} = \frac{7}{19}$

Stream:JEESubject:ChemistryTopic:Liquid SolutionSubtopic:Raoult's Law

⏱ 2mℹ️ Source: QB

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