Two liquids A and B form an ideal solution at temperature T . When the total vapour pressure above the solution is 600 Torr , then mole fraction of A in the vapour phase is 0.35 and in the liquid phas

Question

Two liquids A and B form an ideal solution at temperature T . When the total vapour pressure above the solution is 600 Torr , then mole fraction of A in the vapour phase is 0.35 and in the liquid phase is 0.70 . If vapour pressure pure ' A ' and pure ' B ' are p ∘ A & p ∘ B then find the value of 10 p ∘ B − 2 p ∘ A ​ (in torr).

TestHub · Accepted Answer

The given data are x A ​ = 0.70 x A ​ = 0.70 y A ​ = 0.35 ​ y A ​ = 0.35 p = 600 Torr ​ p = 600 Torr p A ∗ ​ = ? ​ p A ∗ ​ = ? p B ∗ ​ = ? ​ p B ∗ ​ = ? ​ Now y A ​ = p p A ​ ​ = p x A ​ p A ∗ ​ ​ Therefore p A ∗ ​ = x A ​ y A ​ p ​ = ( 0.70 ) ( 0.35 ) ( 600 Tor ) ​ = 300 Torr Similarly, p B ∗ ​ = x B ​ y B ​ p ​ = ( 0.30 ) ( 0.65 ) ( 600 Torr ) ​ = 1300 Torr

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