A 0.1 molal aqueous solution of K 3 [ Fe(CN) 6 ] freezes at − 0.85 ∘ C. If K f for water is 1.86 K kg mol − 1 , what is the van't Hoff factor for this solution?

Question

A 0.1 molal aqueous solution of K 3 ​ [ Fe(CN) 6 ​ ] freezes at − 0.85 ∘ C. If K f ​ for water is 1.86 K kg mol − 1 , what is the van't Hoff factor for this solution?

TestHub · Accepted Answer

The depression in freezing point is given by the equation:

$Δ T_{f} = i \cdot K_{f} \cdot m$

From the given data:

$Δ T_{f} = 0.85$

$K_{f} = 1.86$

$m = 0.1$

Substituting the values into the equation:

$0.85 = i \cdot 1.86 \cdot 0.1$

$i = \frac{0.85}{0.186}$

$i \approx 4.57$

Answer: $4.57$

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