Calculate the mass of solute dissolved in $100$ g solvent that produces boiling point elevation $0.5$ K.
[ $K_{b}$ for solvent $= 2$ $K kg mol^{- 1}$ $&$ Molar mass of solute $= 120$ $g mol^{- 1}$ ]

Question

Calculate the mass of solute dissolved in 100 g solvent that produces boiling point elevation 0.5 K. [ K b ​ for solvent = 2 K kg mol − 1 & Molar mass of solute = 120 g mol − 1 ]

TestHub · Accepted Answer

Using the formula for elevation in boiling point:

$Δ T_{b} = K_{b} \times m$

$Δ T_{b} = \frac{1000 \times K _{b} \times W _{B}}{M \times W _{A}}$

Substituting the given values:

$0.5 = \frac{1000 \times 2 \times W _{B}}{120 \times 100}$

$0.5 = \frac{2000 \times W _{B}}{12000}$

$0.5 = \frac{W _{B}}{6}$

$W_{B} = 3$ g

Answer: $3$ g.

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