Chemistry - Liquid Solution Question with Solution | TestHub

According to Henry's law, the solubility of a gas in a liquid is directly proportional to the partial pressure of the gas above the liquid.

$S=K_{H}P$

Where $S$ is the solubility, $K_H$ is Henry's law constant, and $P$ is the partial pressure.

Given:
$S=5.14\times 10^{-4}{\text{ mol dm}}^{-3}$
$P=0.75\text{ bar}$

$K_H=\frac{S}{P}=\frac{5.14\times 10^{-4}}{0.75}$

$K_H=6.85\times 10^{-4}{\text{ mol dm}}^{-3}{\text{ bar}}^{-1}$

Answer: $6.85\times 10^{-4}\mathrm{mol}{\mathrm{dm}}^{-3}{\mathrm{bar}}^{-1}$