Chemistry - Liquid Solution Question with Solution | TestHub

The elevation in boiling point for the $0.1$ molal solution is $\Delta T_{b1}=100.16^{\circ }\mathrm{C}-100^{\circ }\mathrm{C}=0.16^{\circ }\mathrm{C}$.

Using the formula $\Delta T_b=K_b\times m$, the elevation in boiling point is directly proportional to the molality of the solution.

$\frac{\Delta T_{b2}}{\Delta T_{b1}}=\frac{m_2}{m_1}$

$\frac{\Delta T_{b2}}{0.16}=\frac{0.5}{0.1}=5$

$\Delta T_{b2}=5\times 0.16=0.80^{\circ }\mathrm{C}$

The boiling point of the $0.5$ molal solution is $100^{\circ }\mathrm{C}+0.80^{\circ }\mathrm{C}=100.80^{\circ }\mathrm{C}$.

Answer: $100.80^{\circ }\mathrm{C}$