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ChemistryLiquid SolutionAbnormal Colligatiove PropertiesMedium2 minPYQ_2023

ChemistryMediumsingle choice

A solution of nonvolatile solute is obtained by dissolving $1.5 g$ in $30 g$ solvent has boiling point elevation $0.65 K$ . Calculate the molal elevation constant if molar mass of solute is $150 g mol^{- 1}$ .

Options:

Answer:

Solution:

$M_{2} = \frac{1000. K _{b} W _{2}}{Δ T _{b} W _{1}} K_{b} = \frac{M _{2}^{2} \times Δ T _{b} \times W _{1}}{1000 \times W _{2}} = \frac{150 \times 0.65 \times 30}{1000 \times 1.5} = 1.95 K kg mol^{- 1}$

Stream:MHT_CETSubject:ChemistryTopic:Liquid SolutionSubtopic:Abnormal Colligatiove Properties

⏱ 2mℹ️ Source: PYQ_2023

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