Calculate osmotic pressure of 0.2 M aqueous KCl solution at 0 ∘ C if van't Hoff factor for KCl is 1.83. [ R = 0.082 dm 3 atm mol − 1 K − 1 ]

π = iMRT = 1.83 × 0.2 × 0.082 × 273 = 8.2 atm

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Chemistry - Liquid Solution Question with Solution | TestHub

ChemistryLiquid SolutionAbnormal Colligatiove PropertiesEasy2 minPYQ_2023

ChemistryEasysingle choice

Calculate osmotic pressure of $0.2 M$ aqueous $KCl$ solution at $0^{\circ} C$ if van't Hoff factor for $KCl$ is $1.83. [R = 0.082 dm^{3}$ atm mol $^{- 1} K^{- 1}]$

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Answer:

Solution:

$π = iMRT = 1.83 \times 0.2 \times 0.082 \times 273 = 8.2 atm$

Stream:MHT_CETSubject:ChemistryTopic:Liquid SolutionSubtopic:Abnormal Colligatiove Properties

⏱ 2mℹ️ Source: PYQ_2023

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