The osmotic pressure of solutions of PVC in cyclohexanone at $300 K$ are plotted on the graph. The molar mass of PVC is $g {mol}^{- 1}$ (Nearest integer)
(Given : $R = 0.083 L atm K^{- 1} {mol}^{- 1}$ )

Question

The osmotic pressure of solutions of PVC in cyclohexanone at 300 K are plotted on the graph. The molar mass of PVC is g mol - 1 (Nearest integer) (Given : R = 0 . 083 L atm K - 1 mol - 1 )

TestHub · Accepted Answer

Using osmotic pressure in ideal gas equation:
$π = M^{'} RT = (\frac{W / M}{V}) RT$

$\Rightarrow π = (\frac{W}{V}) (\frac{1}{M}) RT = C (\frac{RT}{M})$

$\Rightarrow \frac{π}{C} = \frac{RT}{M}$

If we assume given graph between $\frac{π}{C}$ and $C$

Slope $= \frac{RT}{M} = \frac{0.083 \times 300}{M} = 6 \times 10^{- 4}$

$∴ M = \frac{0.083 \times 300}{6 \times 10^{- 4}} = \frac{830 \times 300}{6}$

$= 41, 500 gm / mole$

Chemistry - Liquid Solution Question with Solution | TestHub

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