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Chemistry - Liquid Solution Question with Solution | TestHub

ChemistryLiquid SolutionAbnormal Colligatiove PropertiesEasy2 minPYQ_2022

ChemistryEasysingle choice

What is the molar mass of solute if a solution is prepared by dissolving 4.5 gram solute in $3 dm^{3}$ water having osmotic pressure $0.25 atm$ at $300 K$ ? $(R = 0.0821 dm^{3} atm K K^{- 1} mol^{- 1})$

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Answer:

Solution:

$π = CRT$ $0.25 = \frac{4.5}{M _{B}} \times \frac{1000}{3000} \times 0.0821 \times 300$ $M_{B} = 147.78 g / mol$

Stream:MHT_CETSubject:ChemistryTopic:Liquid SolutionSubtopic:Abnormal Colligatiove Properties

⏱ 2mℹ️ Source: PYQ_2022

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