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Chemistry - Liquid Solution Question with Solution | TestHub

ChemistryLiquid SolutionAbnormal Colligatiove PropertiesMedium2 minPYQ_2021

ChemistryMediumsingle choice

What is cryoscopic constant of water if $5 g$ of glucose in $100 g$ of water has depression in freezing point $2.15 K$ ? (Molar mass of glucose $= 180$ )

Options:

Answer:

Solution:

$Δ T_{f} = kf \cdot m m (molality) = \frac{moles of glucose}{massof water ( kg )} m = \frac{5/180}{0.1 kg} = \frac{5}{18} mol / kg Δ T_{f} = 2.15 K 2.15 = K_{f} \cdot \frac{5}{18} K_{f} = 7.74 K kg mol$

Stream:MHT_CETSubject:ChemistryTopic:Liquid SolutionSubtopic:Abnormal Colligatiove Properties

⏱ 2mℹ️ Source: PYQ_2021

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