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Chemistry - Liquid Solution Question with Solution | TestHub

ChemistryLiquid SolutionAbnormal Colligatiove PropertiesMedium2 minPYQ_2021

ChemistryMediumsingle choice

Calculate osmotic pressure exerted by a solution containing $0.822 g$ of solute in $300 mL$ of water at $300 K$ . (Molar mass of solute $= 340 mol^{- 1}, R = 0.0821 L atm mol^{- 1} K^{- 1}$ )

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Answer:

Solution:

$π = CRT C = \frac{moles of solute}{volumeof solution ( ml )} \times 1000 = \frac{0.822/340}{300} \times 1000 = 0.008 π = 0.008 \times 0.0821 \times 300 π = 0.2 atm$

Stream:MHT_CETSubject:ChemistryTopic:Liquid SolutionSubtopic:Abnormal Colligatiove Properties

⏱ 2mℹ️ Source: PYQ_2021

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