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Chemistry - Liquid Solution Question with Solution | TestHub

ChemistryLiquid SolutionAbnormal Colligatiove PropertiesMedium2 minPYQ_2021

ChemistryMediumsingle choice

If $6 g$ of solute dissolved in $100 g$ of water lowers the freezing point by $0.93 K$ . What is molar mass of solute? $(K_{f} = 1.86 K kg mol^{- 1})$

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Answer:

Solution:

$m = \frac{moles of solute}{mass of solvent} \times 1000 = \frac{6/ M}{100} \times 1000 = \frac{60}{M} Δ T_{f} = K_{f} \cdot m 0.93 = 1.86 \times \frac{60}{M} \Rightarrow M = \frac{1.86 \times 60}{0.93} = 120 g mol^{- 1}$

Stream:MHT_CETSubject:ChemistryTopic:Liquid SolutionSubtopic:Abnormal Colligatiove Properties

⏱ 2mℹ️ Source: PYQ_2021

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