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Chemistry - Liquid Solution Question with Solution | TestHub

ChemistryLiquid SolutionAbnormal Colligatiove PropertiesEasy2 minPYQ_2020

ChemistryEasysingle choice

An aqueous solution contains 5% by mass of urea and 10% by mass of glucose. If $K_{f}$ for water is $1.86 K kg {mol}^{- 1},$ the freezing point of the solution is

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Answer:

Solution:

Moles of solute $= \frac{5}{60} + \frac{10}{180} = \frac{25}{180}$
$Molality = \frac{n × 1000}{weight of solvent}$
Molality of solution $= \frac{25 \times 1000}{180 \times 85}$
$Δ T_{f} = \frac{25 \times 1000 \times 1.86}{180 \times 85} = 3.03$
$F . P . = 0 - 3.03^{o} C = - 3.03^{o} C$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Liquid SolutionSubtopic:Abnormal Colligatiove Properties

⏱ 2mℹ️ Source: PYQ_2020

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