Chemistry - Liquid Solution Question with Solution | TestHub

since same lowering in vapour pressure.
${\text{X}}_{\text{solute of urea }}={\text{X}}_{\text{solute of glucose }}$
$\frac{\frac{1}{60}}{\frac{1}{60}+\frac{50}{18}}=\frac{\frac{w}{180}}{\frac{w}{180}+\frac{100}{18}}\Rightarrow \frac{\frac{1}{60}}{\frac{50}{18}}=\frac{\frac{w}{180}}{\frac{100}{18}}$(For dilute solution)
$\Rightarrow w=6\text{of}\text{glucose}$