Chemistry - Liquid Solution Question with Solution | TestHub

${\text{p}}_{\text{Total}}={\text{p}}_{\text{A}}^{\circ }{\text{X}}_{\text{A}}+{\text{p}}_{\text{B}}^{\circ }{\text{X}}_{\text{B}}$

$=100\times \frac{1}{5}+200\times \frac{4}{5}$

$=20+160=180$

(Vapours are condensed and again brought in equilibrium with vapours).

i.e for distillate

y_A→ to be replaced by x_A

y_B→ to be replaced by x_B.

${\text{y}}_{\text{A}}=\frac{{\text{p}}_{\text{A}}^{\text{o}}{\text{x}}_{\text{A}}}{{\text{p}}_{\text{T}}}=\frac{20}{180}$

${\text{y}}_{\text{B}}=\frac{{\text{p}}_{\text{B}}^{\text{o}}{\text{x}}_{\text{B}}}{{\text{p}}_{\text{T}}}=\frac{160}{180}$

${\text{P}}_{\text{distillate}}=\frac{100\times 20}{180}+\frac{200\times 160}{180}$

= 188.88