Chemistry - Liquid Solution Question with Solution | TestHub

${\text{p}}_{\text{T}}=\text{0.983 atm}$

${\text{p}}_{\text{water}}^{\circ }=\text{0.84 atm}$

$\therefore$${\text{p}}_{\text{liquid}}^{\circ }=\text{0.143 atm}$

Apply Dalton's law of vapour phase

$\frac{{\text{p}}^{\text{o}}\text{water}}{{\text{p}}^{\text{o}}\text{liquid}}=\frac{\text{0.84}}{\text{0.143}}=\frac{n_{H_{2}O}}{n_{Liquid}}$

$\frac{\text{0.84}}{\text{0.143}}=\frac{\frac{\text{1}}{\text{18}}}{\frac{{\text{w}}_{\text{e}}}{\text{134.3}}}=\frac{\text{134.3}}{\text{18}\times {\text{w}}_{\text{e}}}$

${\text{w}}_{\text{e}}=\frac{\text{134.3}}{\text{18}}\times \frac{\text{0.143}}{\text{0.84}}=\text{1.27 g}$