Chemistry - Liquid Solution Question with Solution | TestHub

ChemistryLiquid SolutionRaoult's LawMedium2 minPYQ_2020
ChemistryMediumnumerical

At300 K, the vapour pressure of a solution containing1mole ofn-hexane and3moles ofn-heptane is550 mmofHg. At the same temperature, if one more mole ofn-heptane is added to this solution, the vapour pressure of the solution increases by10 mmofHg. What is the vapour pressure inmmHgofn- heptane in its pure state______?

Answer:
600.00
Solution:

Ptotal=P∘hexane. Xhexane+P∘heptane.Xheptane

550=P∘hexane×14+P∘heptane×34     ..(i)

After mixing 1 mole n-heptane

560=P∘hexane×15+P∘heptane×45     .....(ii)

On solving eq. (i) and (ii)

P∘heptane=600 mm of Hg

Stream:JEESubject:ChemistryTopic:Liquid SolutionSubtopic:Raoult's Law
⏱ 2mℹ️ Source: PYQ_2020

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