The value of Henry's law constant for few gases at 298 K is given below. Arrange these gases in the increasing order of their solubility.
$N_{2}$ : 76.48 kbar, $O_{2}$ : 34.86 kbar, $H_{2}$ : 69.16 kbar

Question

The value of Henry's law constant for few gases at 298 K is given below. Arrange these gases in the increasing order of their solubility. N 2 : 76.48 kbar, O 2 : 34.86 kbar, H 2 : 69.16 kbar

TestHub · Accepted Answer

As higher the value of K H , lower is the solubility of gas in the liquid so the correct order of solubility of these gases is as follows K H N 2 76.48 < H 2 69.16 < O 2 34.86

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