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ChemistryLiquid SolutionAbnormal Colligatiove PropertiesMedium2 minPYQ_2020

ChemistryMediumsingle choice

$0.5$ molal aqueous solution of a weak acid $(HX)$ is $20%$ . ionised. If $K_{f}$ of water is $1.86 K kg mol^{- 1}$ , the lowering in freezing point of solution is

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Solution:

$HX ⇌ H^{+} + X^{-}$ For dissociation of an electrolyte, $α = \frac{i - 1}{n - 1} ∴ 0.2 = \frac{i - 1}{2 - 1}$ $∴ i - 1 = 0.2$ $∴ i = 0.2 + 1 = 1.2$ Now, $Δ T_{f} = i k_{f} m = 1.2 \times 1.86 \times 0.5 = 1.12 K$

Stream:MHT_CETSubject:ChemistryTopic:Liquid SolutionSubtopic:Abnormal Colligatiove Properties

⏱ 2mℹ️ Source: PYQ_2020

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