Chemistry - Liquid Solution Question with Solution | TestHub

ChemistryLiquid SolutionAbnormal Colligatiove PropertiesEasy2 minPYQ_2020

ChemistryEasysingle choice

The ratio of the value of any colligative property for $K_{4} [F e (C N)_{6}]$ to that of $F e_{4} [F e (C N)_{6}]_{3}$ solution is nearly

Options:

Answer:

Solution:

van't Hoff factor of $K_{4} [F e (C N)_{6}] = 5$
$K_{4} [F e (C N)_{6}] = 4 K^{+} + [F e (C N)_{6}]^{4 -}$
van't Hoff factor of $F e_{4} [F e (C N)_{6}]_{3} = 7$
$F e_{4} [F e (C N)_{6}]_{3} = 4 F e^{3 +} + 3 [F e (C N)_{6}]^{4 -}$
So ratio of colligative properties $= \frac{5}{7} = 0.71$ .

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Liquid SolutionSubtopic:Abnormal Colligatiove Properties

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...