Chemistry - Liquid Solution Question with Solution | TestHub

Lowering in freezing point is a colligative property, colligative property depends on the number of molecule atom or ions and molality. In 0.1 m NaCl. Molality is maximum out of four and NaCl dissociates into$\mathrm{N}{\mathrm{a}}^{+},\mathrm{C}{\mathrm{l}}^{-}$(i = 2).
Colligative property$\propto \mathrm{m}\times \mathrm{i}$
So, 0.1 m NaCl > 0.1 m${\mathrm{C}}_2{\mathrm{H}}_5\mathrm{O}\mathrm{H}$> 0.01 m NaCl > 0.01 m${\mathrm{C}}_2{\mathrm{H}}_5\mathrm{O}\mathrm{H}$