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ChemistryLiquid SolutionMiscellaneous/MixedEasy2 minPYQ_2020

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A $5.25 %$ solution of a substance is isotonic with a $1.5 %$ solution of urea (molar mass = $60 g {mol}^{- 1}$ ) in the same solvent. If the densities of both the solutions are assumed to be equal to $1.0 g {cm}^{- 3}$ , molar mass of the substance will be

Options:

Answer:

Solution:

$π_{s o l u t i o n} = π_{u r e a}$
$\frac{5.25}{M} = \frac{1.5}{60}$
$M = \frac{5.25 \times 60}{1.5}$
$= 210.0 g {mol}^{- 1}$

Stream:NTA_ABHYASSubject:ChemistryTopic:Liquid SolutionSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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