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ChemistryLiquid SolutionMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasynumerical

1.22 g C₆H₅COOH is added into the 100 g solvent CH₃COCH₃where data of Δ T_band K_bare given as:
ΔT_b= 0.17, solute by K_b= 1.7 K kg/mol
Find out the molecular weight (g/mol) of the solute in the solution by interpreting the result.

Answer:

122.00

Solution:

$Δ T_{b} = 0.17 = K_{b} \cdot m$
$0.17 = 1.7 \times \frac{1.22/M}{100/1000}$
M = 122 g/mole
Benzoic acid is not associated or dissociated.

Stream:NTA_ABHYASSubject:ChemistryTopic:Liquid SolutionSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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