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ChemistryLiquid SolutionMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasysingle choice

The vapor pressure of benzene is $53.3 k P_{a}$ at $603^{o} C$ , but it falls to $51 .5 {kP}_{a}$ when $19 g$ of a non-volatile organic compound is dissolved in $500 g$ benzene. The molar mass of the non-volatile compound is

Options:

Answer:

Solution:

$P^{0} = 53 .3 kPa$
$P_{s} = 51.5 {kP}_{a}$
$\frac{P^{0} - P_{s}}{P_{s}} = \frac{n}{N} = \frac{19 \times 78}{M \times 500}$
$\frac{53.3 - 51.5}{51.5} = \frac{n}{N} = \frac{19 \times 78}{M \times 500}$
$M = \frac{19 \times 78 \times 51.5}{(53.3 - 51.5) \times 500}$
$M = 85 g$

Stream:NTA_ABHYASSubject:ChemistryTopic:Liquid SolutionSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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