Start Free Mock LoginAlready registered? Login here

Chemistry - Liquid Solution Question with Solution | TestHub

ChemistryLiquid SolutionAbnormal Colligatiove PropertiesEasy2 minPYQ_2020

ChemistryEasysingle choice

The boiling point of a glucose solution containing 12 g of glucose in 100 g of water is 100. $34 ° C$ . Boiling point of water is $100 °$ C. The molal elevation constant of water is

Options:

Answer:

Solution:

$Δ T_{b} = 100.34 - 100 = 0.34 ° C$
$∆ T_{b} = \frac{k_{b} \times w_{2} \times 1000}{M_{2} \times w_{1}}$
$k_{b} = \frac{∆ T_{b} \times M_{2} \times w_{1}}{w_{2} \times 1000}$
$k_{b} = \frac{0.34 \times 180 \times 100}{12 \times 1000} = 0.51$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Liquid SolutionSubtopic:Abnormal Colligatiove Properties

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...