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Chemistry - Liquid Solution Question with Solution | TestHub

ChemistryLiquid SolutionRaoult's LawMedium2 minPYQ_2020

ChemistryMediumsingle choice

If $8 g$ of a non-electrolyte solute is dissolved in $114 g$ of $n -$ octane to reduce its vapour pressure to $80 %,$ the molar mass (in $g {mol}^{- 1}$ ) of the solute is [Given that molar mass of n-octane is $114 g {mol}^{- 1}$ ]NEET 2020 (Phase 2)

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Answer:

Solution:

Assuming dilute solution,
$\frac{P_{0} - P_{s}}{P_{s}} \approx \frac{P_{0} - P_{s}}{P_{0}} = \frac{n_{solute}}{n_{solvent}}$
Let $P_{0} = 100,$ V.P reduced to $80 %, ∴ P_{s} = 80$
$\frac{100 - 80}{100} = \frac{8 / m}{114 / 114}$
$m = 40$ g/mol.

Stream:NEETSubject:ChemistryTopic:Liquid SolutionSubtopic:Raoult's Law

⏱ 2mℹ️ Source: PYQ_2020

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