Chemistry - Liquid Solution Question with Solution | TestHub

K_H= 4.27 × 10⁵mm Hg (at 298 K)

p = 760 mm

Applying Henry's law

p = K_Hx [x = Mole fraction / solubility of methane]

$\text{x}=\frac{\text{p}}{{\text{K}}_{\text{H}}}=\frac{\left(\text{760 mm}\right)}{\left(\text{4.27}\times {\text{10}}^5\text{mm}\right)}=\text{178}\times {\text{10}}^{-5}=\text{1.78}\times {\text{10}}^{-3}$