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ChemistryLiquid SolutionRaoult's LawHard2 minPYQ_2019
ChemistryHardsingle choice

9 gram anhydrous oxalic acid (mol. Wt. = 90) was dissolved in 9.9 moles of water. If vapour pressure of pure water isP1octhe vapour pressure of solution is

Options:

Answer:
A
Solution:

The total vapour pressure of a solution in this case only depends on vapour pressure of water as anhydrous oxalic acid is a non-volatile compound.
∴Vapour pressure of solution = vapour pressure of
WaterPw
According to Raoult’s law
Number of moles of oxalic acid =990=0.1moles
∴        xw=9.99.9+0.1=0.99
⇒             Ps=Pw=0.99×P1o

Stream:MHT_CETSubject:ChemistryTopic:Liquid SolutionSubtopic:Raoult's Law
⏱ 2mℹ️ Source: PYQ_2019

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