Chemistry - Liquid Solution Question with Solution | TestHub

$\begin{array}{rl}& \text{ Molarity (M) }\\ & =\frac{\text{ mass of solute (in }\mathrm{g})}{\text{ molecular weight of solute }}=\frac{222\mathrm{g}}{111\mathrm{g}{\mathrm{mol}}^{-1}\times 1\mathrm{L}}\\ & \times \text{ Volume of solution (in }\mathrm{L}\text{ ) }\\ & \left[\because \text{ Molecular weight of }{\mathrm{CaCl}}_2=111\mathrm{g}{\mathrm{mol}}^{-1}\right]\\ & =0.2\mathrm{mol}{\mathrm{L}}^{-1}=0.2\mathrm{M}.\end{array}$