Chemistry - Liquid Solution Question with Solution | TestHub

$\mathrm{p}\hspace{0.33em}=\hspace{0.33em}{\mathrm{K}}_{\mathrm{H} }\mathrm{X}$
where$\mathrm{p}\to$Partial pressure of gas
${\mathrm{X}}_{\mathrm{2}}\to$Mole fraction of gas in solution
${\mathrm{K}}_{\mathrm{H}}\hspace{0.33em}=$Henry's law constant
So,$\mathrm{p}\propto$solubility
$\frac{{\mathrm{p}}_{\mathrm{1}}}{{\mathrm{p}}_{\mathrm{2}}}\hspace{0.33em}=\mathrm{\hspace{0.33em}}\frac{{\mathrm{s}}_{\mathrm{1}}}{{\mathrm{s}}_{\mathrm{2}}}\mathrm{\hspace{0.33em}}\Rightarrow \mathrm{\hspace{0.33em}}\frac{\mathrm{500}}{\mathrm{0}.01}\hspace{0.33em}=\mathrm{\hspace{0.33em}}\frac{\mathrm{750}}{\mathrm{x}}$
$\therefore \mathrm{\hspace{0.33em}}\mathrm{x}\hspace{0.33em}=\hspace{0.33em}0.015\mathrm{\hspace{0.33em}}\mathrm{g}/\mathrm{L}$