The freezing point (in ∘ C ) of solution containing 0.1 g of K 3 [ Fe ( CN ) 6 ] (molecular weight 329 ) in 100 g of water ( K f = 1.86 K kg mol − 1 ) is

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The freezing point (in ∘ C ) of solution containing 0.1 g of K 3 ​ [ Fe ( CN ) 6 ​ ] (molecular weight 329 ) in 100 g of water ( K f ​ = 1.86 K kg mol − 1 ) is

TestHub · Accepted Answer

vant Hoff's factor ( i ) = 4 { 3 K + + [ Fe ( CN ) 6 ​ ] 3 − } Molality = 329 0.1 ​ × 100 1000 ​ = 329 1 ​ ⇒ − Δ T f ​ = i K f ​ ⋅ m = 4 × 1.86 × 329 1 ​ = 2.3 × 1 0 − 2 ⇒ T f ​ = − 2.3 × 1 0 − 2 ∘ C (As freezing point of water is 0 ∘ C )

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