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Chemistry - Liquid Solution Question with Solution | TestHub

ChemistryLiquid SolutionAbnormal Colligatiove PropertiesEasy2 minPYQ_2011

ChemistryEasysingle choice

The freezing point depression constant for water is $- 1.8 6^{\circ} C m^{- 1}$ . If $5.00 g Na SO_{4}$ is dissolved in $45.0 g H_{2} O$ , the freezing point is changed by $- 3.8 2^{\circ} C$ . Calculate the van't Hoff factor for $Na_{2} SO_{4}$ .NEET 2011 (Screening)

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Answer:

Solution:

$Δ T_{f} or i = i \times K_{f} \cdot m = \frac{Δ T _{f} \times W _{solvent}}{K _{f} \times n _{solute} \times 1000} = \frac{3.82 \times 45}{1.86 \times ( \frac{5}{142} ) \times 1000} = 2.63$

Stream:NEETSubject:ChemistryTopic:Liquid SolutionSubtopic:Abnormal Colligatiove Properties

⏱ 2mℹ️ Source: PYQ_2011

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