The freezing point of a solution composed of 10.0 gof KCl in 100 g of water is 4. 5 ∘ C . Calculate the van't Hoff factor, i for this solution.

Δ T f = i K f m m = 74.55 × 100 10 × 1000 = 1.34 m [ Molecular Mass of KCl = 74.55 ] i = K f m Δ T f = ( 1.8 6 ∘ C / m ) ( 1.34 m ) 4. 5 ∘ C = 1.8

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Chemistry - Liquid Solution Question with Solution | TestHub

ChemistryLiquid SolutionAbnormal Colligatiove PropertiesEasy2 minPYQ_2011

ChemistryEasysingle choice

The freezing point of a solution composed of $10.0$ gof $KCl$ in $100 g$ of water is $4. 5^{\circ} C$ . Calculate the van't Hoff factor, i for this solution.

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Answer:

Solution:

$Δ T_{f} = i K_{f} m m = \frac{10 \times 1000}{74.55 \times 100} = 1.34 m [Molecular Mass of KCl = 74.55] i = \frac{Δ T _{f}}{K _{f} m} = \frac{4. 5 ^{\circ} C}{( 1.8 6 ^{\circ} C / m ) ( 1.34 m )} = 1.8$

Stream:VITEEESubject:ChemistryTopic:Liquid SolutionSubtopic:Abnormal Colligatiove Properties

⏱ 2mℹ️ Source: PYQ_2011

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