Chemistry - Liquid Solution Question with Solution | TestHub

$\begin{array}{rl}\frac{p^{\circ }-p_s}{p^{\circ }}=\frac{n}{n+N}& =\frac{\frac{w}{m}}{\frac{w}{m}+\frac{W}{M}}\\ \because \frac{w}{m}& <\frac{W}{M}\\ \therefore \frac{p^{\circ }-p_s}{p^{\circ }}& =\frac{w/m}{W/M}=\frac{w}{m}\times \frac{M}{W}\\ \frac{3000-2985}{3000}& =\frac{5}{m}\times \frac{18}{100}\\ m& =\frac{5\times 18\times 3000}{15\times 100}\\ m& =180\end{array}$ 180 is the molecular weight of glucose $\left({\mathrm{C}}_6{\mathrm{H}}_{12}{\mathrm{O}}_6\right)$, thus the substance ' $X$ ' is glucose.