Chemistry - Liquid Solution Question with Solution | TestHub

Given, volume of ${\mathrm{H}}_2{\mathrm{SO}}_4$ before dilution, $V_1=2.5{\mathrm{cm}}^3$ $$=2.5\times 10^{-3}{\mathrm{dm}}^3$$ volume of ${\mathrm{II}}_2{\mathrm{SO}}_4$ after dilution, $V_2-0.5{\mathrm{dm}}^3$ Concentration of ${\mathrm{H}}_2{\mathrm{SO}}_4$ before dilution $=0.2\mathrm{M}$ $$=0.4\mathrm{N}[\because 1\mathrm{N}=2\mathrm{M}]$$ Concentration (normality) of ${\mathrm{H}}_2{\mathrm{SO}}_4$ after dilution, $N_2=$ ? Normality equation is $$N_1{V}_1=N_2{V}_2$$ (before dilution) (after dilution) $$\begin{array}{rl}2.5\times 10^{-3}\times 0.4& =N_2\times 0.5\\ N_2& =\frac{2.5\times 10^{-3}\times 0.4}{0.5}\\ & =2\times 10^{-3}=0.002\mathrm{N}\end{array}$$