The following titration curve was obtained as part of a general chemistry laboratory experiment for an unknown that weighed 0.8 g . The titrant was either a 0.2 M strong base or 0.2 M strong acid. If the molar mass of the unknown is $M$ , the value of $\frac{M}{20}$ is

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As the pH keeps on decreasing, the titrant must be an acid and the unknown, a base. The shape of the curve reveals that it is a monoacidic base. The end point is reached at a volume of 50 mL .

$\frac{0.8}{M} = 0.2 \times 50 \times 1 0^{- 3} \Rightarrow M = 80 u$

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