Chemistry - Ionic Equilibrium Question with Solution | TestHub
ChemistryIonic EquilibriumBuffer solutionEasy2 minQB
ChemistryEasynumerical
26.5 g Na₂CO₃ in 500 mL water is mixed with 150 mL 1 M HCl. Find pOH; , ,log2=0.3,log3=0.477.
Answer:
4.00
Solution:
Initial carbonate=26.5/106=0.25 mol. HCl=0.150 mol converts that much to bicarbonate, leaving 0.100 mol carbonate and 0.150 mol bicarbonate. pH=10.177+log(0.100/0.150)=10.177+0.300-0.477=10.000. Therefore pOH=4.
Stream:JEESubject:ChemistryTopic:Ionic EquilibriumSubtopic:Buffer solution
⏱ 2mℹ️ Source: QB
Doubts & Discussion
Loading discussions...
