The first and second dissociation constants of an acid H 2 A are 1.0 × 1 0 − 5 and 5.0 × 1 0 − 10 respectively. The overall dissociation constant of the acid will be :

K Overall = K a 1 × K a 2 = 1 × 1 0 − 5 × 5 × 1 0 − 10 = 5 × 1 0 − 15

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ChemistryIonic EquilibriumpH of Polyprotic Acids and BasesMedium2 minQB

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The first and second dissociation constants of an acid $H_{2} A$ are $1.0 \times 1 0^{- 5}$ and $5.0 \times 1 0^{- 10}$ respectively. The overall dissociation constant of the acid will be :

Options:

Answer:

Solution:

$K_{Overall} = K_{a_{1}} \times K_{a_{2}}$

$= 1 \times 1 0^{- 5} \times 5 \times 1 0^{- 10} = 5 \times 1 0^{- 15}$

Stream:JEESubject:ChemistryTopic:Ionic EquilibriumSubtopic:pH of Polyprotic Acids and Bases

⏱ 2mℹ️ Source: QB

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