20 mL of 0.2 M HA (strong acid), 20 mL of 0.1 M H 2 B (strong dibasic acid) and 30 mL of 0.2 N M ( OH ) 2 (strong base) are mixed and the volume is made up to 100 mL with water. What is the pOH of

Question

20 mL of 0.2 M HA (strong acid), 20 mL of 0.1 M H 2 ​ B (strong dibasic acid) and 30 mL of 0.2 N M ( OH ) 2 ​ (strong base) are mixed and the volume is made up to 100 mL with water. What is the pOH of the final solution? [Given lo g 2 = 0.3 ]

TestHub · Accepted Answer

Acid: HA gives 20 × 0.2 = 4 meq. H 2 ​ B gives 20 × 0.1 × 2 = 4 meq. Total H + = 8 meq. Base: 30 × 0.2 = 6 meq OH − . Excess H + = 2 meq in 100 mL: [ H + ] = 0.02 M . pH = 2 − lo g 2 = 1.7 , so pOH = 14 − 1.7 = 12.3 . Answer: (D).

Chemistry - Ionic Equilibrium Question with Solution | TestHub

Options:

Doubts & Discussion