Chemistry - Ionic Equilibrium Question with Solution | TestHub

Explanation Question: Find volume of $0.2\mathrm{m}{\mathrm{RNH}}_3\mathrm{Cl}$

Concept: This question is based on Buffer solution

Solution: Ozonolysis

$${\mathrm{P}}_{\mathrm{Ob}}={\mathrm{P}}_{\mathrm{Kb}}+\log \frac{\left[{\mathrm{RNH}}_3\mathrm{Cl}\right]}{\left[{\mathrm{RNH}}_2\right]}$$

$14-8.7=5+\log \left(\frac{0.2\times \mathrm{V}}{0.1\times 100}\right)$

$0.3=\log 2=\log \left(\frac{0.2\times \mathrm{V}}{10}\right)$

$\frac{0.2\times V}{10}=2$

$\mathrm{V}=100\mathrm{ml}$