The dissociation constants of a weak acid HA and weak base BOH are 2 × 1 0 − 5 and 5 × 1 0 − 6 respectively. The equilibrium constant for the neutralization reaction of the two is a × 1 0 b (in scient

Question

The dissociation constants of a weak acid HA and weak base BOH are $2 \times 1 0^{- 5}$ and $5 \times 1 0^{- 6}$ respectively. The equilibrium constant for the neutralization reaction of the two is $a \times 1 0^{b}$ (in scientific notation), then $(a + b) =$ ?

Answer:

5

Solution:

For neutralization, $K = \frac{1}{K _{h}} = \frac{K _{a} K _{b}}{K _{w}} = 1 \times 1 0^{4}$

TestHub · Accepted Answer

For neutralization, K = K h ​ 1 ​ = K w ​ K a ​ K b ​ ​ = 1 × 1 0 4

Chemistry - Ionic Equilibrium Question with Solution | TestHub

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