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Chemistry - Ionic Equilibrium Question with Solution | TestHub

ChemistryIonic EquilibriumpH of Polyprotic Acids and BasesEasy2 minQB

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Approximate pH of 0.40 M aqueous solution of a weak diprotic acid $H_{2} X$ with $K_{1} = 1 0^{- 9}$ and $K_{2} = 1 0^{- 15}$ at $2 5^{\circ} C$ is: ( $lo g 2 = 0.3$ )

Options:

Answer:

Solution:

$K_{2}$ is negligible, so only the first ionisation counts.

$[H^{+}] = K_{1} C = 1 0^{- 9} \times 0.4 = 2 \times 1 0^{- 5} M$ .

$pH = 5 - lo g 2 = 4.7$ .

Answer: (A).

Stream:JEESubject:ChemistryTopic:Ionic EquilibriumSubtopic:pH of Polyprotic Acids and Bases

⏱ 2mℹ️ Source: QB

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