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Chemistry - Ionic Equilibrium Question with Solution | TestHub

ChemistryIonic EquilibriumHydrolysis of SaltsMedium2 minPYQ_2024

ChemistryMediumsingle choice

A 0.02 M solution of pyridinium hydrochloride has $pH = 3.44$ . The ionisation constant of pyridine is

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Answer:

Solution:

Pyridine hydrochloride is a salt of weak base and strong acid Hence , $pH = - \frac{1}{2} [lo g K_{w} - lo g K_{b} + lo g C]$ i.e. $3.44 lo g K_{b} K_{b} = - \frac{1}{2} [- 14 - lo g K_{b} + lo g (2 \times 1 0^{- 2}) = - 8.82 = 1.5 \times 1 0^{- 9}$

Stream:VITEEESubject:ChemistryTopic:Ionic EquilibriumSubtopic:Hydrolysis of Salts

⏱ 2mℹ️ Source: PYQ_2024

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