The solubility of A g C l s with solubility product 1.6 × 10 - 10 in 0.1 M N a C l solution would be

∴ K s p A g C l = S S + 0.1 ∵ S ≪ 0.1 ∴ S + 0.1 ≈ 0.1 ∴ 1.6 × 10 - 10 = S × 0.1 ∴ S = 1.6 × 10 - 9 M

Chemistry - Ionic Equilibrium Question with Solution | TestHub

ChemistryIonic EquilibriumSolubility ProductEasy2 minPYQ_2020

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The solubility of $A g C l (s)$ with solubility product $1.6 \times 10^{- 10}$ in $0.1 M N a C l$ solution would be

Answer:

Solution:

$∴ K_{s p (A g C l)} = S (S + 0.1)$

$∵ S ≪ 0.1$

$∴ S + 0.1 \approx 0.1$

$∴ 1.6 \times 10^{- 10} = S \times 0.1$

$∴ S = 1.6 \times 10^{- 9} M$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Ionic EquilibriumSubtopic:Solubility Product

⏱ 2mℹ️ Source: PYQ_2020

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