Chemistry - Ionic Equilibrium Question with Solution | TestHub

ChemistryIonic EquilibriumSolubility ProductEasy2 minPYQ_2020

ChemistryEasysingle choice

Solubility of calcium phosphate (molecular mass, M) in water is W g per 100 mL at 25°C. Its solubility product at 25°C will be approximately.

Answer:

Solution:

Solubility $S = \frac{10 W}{M} m o l e / l i t$
$K_{s p}$ of $C a_{3} (P O_{4})_{2} = 108 S^{5}$
$= 108 \times 1 0^{5} {(\frac{W}{M})}^{5}$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Ionic EquilibriumSubtopic:Solubility Product

⏱ 2mℹ️ Source: PYQ_2020

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